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Cv = Breaking strength loss factorPp = Power at drive pulley in Newton.V = belt speed in m/sec.An Example of Conveyor Belt CalculationsInput data:Conveyor capacity (Cc) = 1500 t/h = 416.67 Kg/secBelt speed (V) = 1.5 m/secConveyor height (H) = 20 mConveyor length (L) = 250 mMass of a set of idlers (mi) = 20 KgIdler spacing (l) = 1.2 mLoad due to belt (mb) = 25 Kg/mInclination angle of the conveyor () = 5 0Coefficient of friction (f) = 0.02Start-up factor (Ks) = 1.5Drive efficiency (Kd) = 0.9Friction factor (Cr) = 15Breaking strength loss factor (Cv) = 0.75Calculation:First, we will use the eqn.1.2 for finding out the load due to idlers:mi = (20/1.2) = 16.67 Kg/mWe will use the eqn.1.1 for finding out the belt tension in steady state:Tb = 1.37*0.02*250*9.81*[16.67+ {2*25+ (416.67/1.5)}*cos (5)] + (20*9.81* (416.67/1.5)) = 77556.88 N.The belt tension while starting the system can be calculated by using the eqn.1.4:Tbs = 1.5 * 77556.88 = 116335.32 NFor calculating the power at drive pulley, we will use the eqn.1.3:Pp = (77556.88*1.5)/ 1000 = 116.335 KwWe will use the eqn.1.5 estimate the size of the motor:Pm = 116.35/0.9 = 129.261 KwWe will use the eqn.1.6 to find out the acceleration of the motor:A = (116335.32 - 77556.88)/ [250*{(2*16.67) + (2*25) + (416.67/1.5)}]= 0.429 m/sec2Lastly, we will use the eqn.1.7 to find out the belt breaking strength:Bs = (15*116.35) / (0.75*1.5) = 1551.33 N/mmThis Bs value is used to select the conveyor belt from the manufacturers catalogue.ConclusionThe conveyor belt calculations methodology discussed in the article is to be used only for the guidance on calculating the initial conveyor design parameters; the final design must be validated by using the FEA or other similar tools before building the prototype.ReferenceDunlop Conveyor belt technique design and calculationBridgestone Conveyor Belt Design Manual

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Austenitic manganese steel was invented by Sir Robert Hadfield in 1882 and was first granted patented in Britain in 1883 with patent number 200. The first United States patents, numbers 303150 and 303151, were granted in 1884. In accordance with ASTM A128 specification, the basic chemical composition of Hadfield steel is 1%1.4% carbon and 11%14% manganese. However, the manganese to carbon ratio is optimum at 10:1 to ensure an austenitic microstructure after quenching [2]. Austenitic manganese steels possess unique resistance to impact and abrasion wears. They exhibit high levels of ductility and toughness, slow crack propagation rates, and a high rate of work-hardening resulting in superior wear resistance in comparison with other potentially competitive materials [310]. These unique properties have made Hadfield's austenitic manganese steel an engineering material of choice for use in heavy industries, such as earth moving, mining, quarrying, oil and gas drilling, and in processing of various materials for components of crushers, mills, and construction machinery (lining plates, hammers, jaws, cones)

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Cv = Breaking strength loss factorPp = Power at drive pulley in Newton.V = belt speed in m/sec.An Example of Conveyor Belt CalculationsInput data:Conveyor capacity (Cc) = 1500 t/h = 416.67 Kg/secBelt speed (V) = 1.5 m/secConveyor height (H) = 20 mConveyor length (L) = 250 mMass of a set of idlers (mi) = 20 KgIdler spacing (l) = 1.2 mLoad due to belt (mb) = 25 Kg/mInclination angle of the conveyor () = 5 0Coefficient of friction (f) = 0.02Start-up factor (Ks) = 1.5Drive efficiency (Kd) = 0.9Friction factor (Cr) = 15Breaking strength loss factor (Cv) = 0.75Calculation:First, we will use the eqn.1.2 for finding out the load due to idlers:mi = (20/1.2) = 16.67 Kg/mWe will use the eqn.1.1 for finding out the belt tension in steady state:Tb = 1.37*0.02*250*9.81*[16.67+ {2*25+ (416.67/1.5)}*cos (5)] + (20*9.81* (416.67/1.5)) = 77556.88 N.The belt tension while starting the system can be calculated by using the eqn.1.4:Tbs = 1.5 * 77556.88 = 116335.32 NFor calculating the power at drive pulley, we will use the eqn.1.3:Pp = (77556.88*1.5)/ 1000 = 116.335 KwWe will use the eqn.1.5 estimate the size of the motor:Pm = 116.35/0.9 = 129.261 KwWe will use the eqn.1.6 to find out the acceleration of the motor:A = (116335.32 - 77556.88)/ [250*{(2*16.67) + (2*25) + (416.67/1.5)}]= 0.429 m/sec2Lastly, we will use the eqn.1.7 to find out the belt breaking strength:Bs = (15*116.35) / (0.75*1.5) = 1551.33 N/mmThis Bs value is used to select the conveyor belt from the manufacturers catalogue.ConclusionThe conveyor belt calculations methodology discussed in the article is to be used only for the guidance on calculating the initial conveyor design parameters; the final design must be validated by using the FEA or other similar tools before building the prototype.ReferenceDunlop Conveyor belt technique design and calculationBridgestone Conveyor Belt Design Manual

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